Find the capacity of a hard disk in database, How many recrods can be stored in a hard disk track? Which of the following is the correct combination of capacity of track, capacity of each surface, and capacity of disk?
Question:
4) Consider a disk with a sector size of 512 bytes, 14409 tracks per surface, 16947 sectors
per track, 8 double-sided platters, and an average seek time of 9 ms. Which of the following is the correct combination of capacity of track, capacity of each surface, and capacity of disk (approximately)?
a) 100 MB, 200 GB, and 2 TB
b) 8 MB, 116 GB and 2 TB
c) 8 MB, 200 GB and 1 TB
d) 80 MB, 116 GB and 1 TB
Answer:
b) 8 MB, 116 GB and 2 TB
Discussion:
Given,
Sector
size -
512 bytes
Number
of sectors per track –
16947
Number
of tracks per surface – 14409
Number
of platters – 8 double-sided
Capacity of a track = sector size * number of sectors per track
=
512 * 16947 = 8 MB approx.
Capacity of each surface = capacity of track * number of tracks per surface
=
(512*16947) * 14409 = 116 GB approx.
Capacity of the disk = capacity of each surface * number of platters * number of pages per platter
= 116 GB * 8 * 2 = 2 TB approx.
Capacity of the disk = capacity of each surface * number of platters * number of pages per platter
= 116 GB * 8 * 2 = 2 TB approx.
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